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I have a symbolic function

syms x

f = -25*x*(- 32*x^10 + 660*x^8 + 27400*x^6 + 304500*x^4 + 900000*x^2 - 2671875)

I want to solve for the zeros...

solve(f == 0,x)

and it returns an empty set. For some weird reason, if I divide f(x) by -25x, it spits out 10 complex roots as expected.

solve(f/(-25*x) == 0,x)

6.6919693149784015130684514768684

1.3248772524381469976203144660927

-1.3248772524381469976203144660927

-6.6919693149784015130684514768684

1.1011196125836762425306399367927 - 3.1220589588466888838496981405409*i

- 1.1011196125836762425306399367927 - 3.1220589588466888838496981405409*i

1.1011196125836762425306399367927 + 3.1220589588466888838496981405409*i

- 1.1011196125836762425306399367927 + 3.1220589588466888838496981405409*i

2.9737480666733788426010418554987*i

-2.9737480666733788426010418554987*i

If I recall, a 10th order polynomial is to large for an analytic solution, but I can not figure out why Matlab fails to find the trivial root x=0 ??? The reason why I ask this is because I'm trying to make plots for an arbitrary order polynomial. You give me an polynomial and I make the plot with a red X at the root locations. In the case above, I can see the roots exists in the plot, but unfortunately, Matlab fails to find the roots in my script using the solve command. How do fix this such that my script is more robust?

John D'Errico
on 30 Aug 2019

Edited: John D'Errico
on 30 Aug 2019

As always, you absolutely need to tell what release you are using, because this works with no problem. Done using R2019a:

syms x

f = -25*x*(- 32*x^10 + 660*x^8 + 27400*x^6 + 304500*x^4 + 900000*x^2 - 2671875);

R = solve(f == 0,x);

vpa(R,10)

ans =

0

-1.324877252

-2.973748067i

- 1.101119613 - 3.122058959i

- 1.101119613 + 3.122058959i

-6.691969315

1.324877252

2.973748067i

1.101119613 + 3.122058959i

1.101119613 - 3.122058959i

6.691969315

numel(R)

ans =

11

So 11 roots. As expected. One of which is zero. As expected.

It is possible that your real problem which is causing an issue also may be due to needing to expand some product (rather then doing the divide by x.) Or, it may be possible that you have an old release. We cannot know what issue you are tripping on, because MATLAB has no problem with what you claim to have done.

John D'Errico
on 30 Aug 2019

I was wondering about an older release, so I cannot easily verify what you are seeing. Without checking, I'm not even sure that R2013 even runs on my current computer. That is a long way back in computer generations.

Note that had you used expand, there would still have been no problem, using solve. The use of vpa is relevant though.

syms x

f = -25*x*(- 32*x^10 + 660*x^8 + 27400*x^6 + 304500*x^4 + 900000*x^2 - 2671875);

>> expand(f)

ans =

800*x^11 - 16500*x^9 - 685000*x^7 - 7612500*x^5 - 22500000*x^3 + 66796875*x

First, see that expand turns this into a simple 11th degree polynomial, which solve will be able to deal with, although no matter what, it generally cannot give you an analytical solution, because the degree of the polynomial is too high. If we extract the zero root, we can see this is a 5th degree polynomial in x^2, and Abel-Ruffini tells us that that problem is in general analytically unsolvable.

See that solve returns a rather unreadable mess here, but vpa resolves that into a set of numeric roots.

solve(expand(f))

ans =

0

-root(z^5 - (165*z^4)/8 - (3425*z^3)/4 - (76125*z^2)/8 - 28125*z + 2671875/32, z, 1)^(1/2)

-root(z^5 - (165*z^4)/8 - (3425*z^3)/4 - (76125*z^2)/8 - 28125*z + 2671875/32, z, 2)^(1/2)

-root(z^5 - (165*z^4)/8 - (3425*z^3)/4 - (76125*z^2)/8 - 28125*z + 2671875/32, z, 3)^(1/2)

-root(z^5 - (165*z^4)/8 - (3425*z^3)/4 - (76125*z^2)/8 - 28125*z + 2671875/32, z, 4)^(1/2)

-root(z^5 - (165*z^4)/8 - (3425*z^3)/4 - (76125*z^2)/8 - 28125*z + 2671875/32, z, 5)^(1/2)

root(z^5 - (165*z^4)/8 - (3425*z^3)/4 - (76125*z^2)/8 - 28125*z + 2671875/32, z, 1)^(1/2)

root(z^5 - (165*z^4)/8 - (3425*z^3)/4 - (76125*z^2)/8 - 28125*z + 2671875/32, z, 2)^(1/2)

root(z^5 - (165*z^4)/8 - (3425*z^3)/4 - (76125*z^2)/8 - 28125*z + 2671875/32, z, 3)^(1/2)

root(z^5 - (165*z^4)/8 - (3425*z^3)/4 - (76125*z^2)/8 - 28125*z + 2671875/32, z, 4)^(1/2)

root(z^5 - (165*z^4)/8 - (3425*z^3)/4 - (76125*z^2)/8 - 28125*z + 2671875/32, z, 5)^(1/2)

>> vpa(solve(expand(f)))

ans =

0

-1.3248772524381469976203144660927

-2.9737480666733788426010418554987i

- 1.1011196125836762425306399367927 + 3.1220589588466888838496981405409i

- 1.1011196125836762425306399367927 - 3.1220589588466888838496981405409i

-6.6919693149784015130684514768684

1.3248772524381469976203144660927

2.9737480666733788426010418554987i

1.1011196125836762425306399367927 - 3.1220589588466888838496981405409i

1.1011196125836762425306399367927 + 3.1220589588466888838496981405409i

6.6919693149784015130684514768684

And, tyes, you can use vpasolve too.

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